2v^2-5v-300=0

Solution for 2v^2-5v-300=0 equation:

2v^2-5v-300=0

a = 2; b = -5; c = -300;
Δ = b2-4ac
Δ = -52-4·2·(-300)
Δ = 2425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2425}=\sqrt{25*97}=\sqrt{25}*\sqrt{97}=5\sqrt{97}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{97}}{2*2}=\frac{5-5\sqrt{97}}{4}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{97}}{2*2}=\frac{5+5\sqrt{97}}{4}
$